(4x^1-2x-4)(2x+4)=

Solution for (4x^1-2x-4)(2x+4)= equation:

Simplifying
(4x + -2x + -4)(2x + 4) = 0

Reorder the terms:
(-4 + 4x + -2x)(2x + 4) = 0

Combine like terms: 4x + -2x = 2x
(-4 + 2x)(2x + 4) = 0

Reorder the terms:
(-4 + 2x)(4 + 2x) = 0

Multiply (-4 + 2x) * (4 + 2x)
(-4(4 + 2x) + 2x * (4 + 2x)) = 0
((4 * -4 + 2x * -4) + 2x * (4 + 2x)) = 0
((-16 + -8x) + 2x * (4 + 2x)) = 0
(-16 + -8x + (4 * 2x + 2x * 2x)) = 0
(-16 + -8x + (8x + 4x2)) = 0

Combine like terms: -8x + 8x = 0
(-16 + 0 + 4x2) = 0
(-16 + 4x2) = 0

Solving
-16 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4x2 = 0 + 16
4x2 = 0 + 16

Combine like terms: 0 + 16 = 16
4x2 = 16

Divide each side by '4'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}